Question

What are solutions to the equation below x^2 +3x-18=0

Answer 1

$x^2 +3x-18=0\\ x^2-3x+6x-18=0\\ x(x-3)+6(x-3)=0\\ (x+6)(x-3)=0\\ x=-6 \vee x=3$

Answer 2

Your solutions would be x = -6 or x = 3.

To find the solutions of this equation you must first factor it by finding factors of -18 that have a difference of 3. This gives you:

(x + 6)(x - 3) = 0

If you set each bracket equal to 0, you can solve for x by either adding 3 or subtracting 6 and get x equal to -6 or 3.

I hope this helps!