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Travka [436]
3 years ago
12

A car was valued at $39,000 in the year 1995. The value depreciated to $11,000 by the year 2003.

Mathematics
1 answer:
denis23 [38]3 years ago
5 0

Answer:

14.6328% , $5836.03

Step-by-step explanation:

Here we are going to use the formula

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=?

A_{8} = 11000

n=8

Hence

39000(1-r)^8 = 11000

(1-r)^8 = \frac{11000}{39000}

(1-r)^8 = 0.2820

(1-r) = 0.2820^{\frac{1}{8}

(1-r) = 0.2820^{0.125}

(1-r) = 0.8536

(1-0.8536=r

r = 0.1463

Hence r= 0.1463

In percentage form r = 14.63%

Now let us see calculate the value of car in 2003 that is after 12 years

we use the main formula again

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=0.1463

A_{12} = ?

n=12

39000(1-0.14634)^{(12} = A_{12}

39000(0.8536)^{12} = A_{12}

39000*0.1497 = A_{12}

A_{12}=5840.34

Hence the car's value will be depreciated to $5840.34 (approx) by 2003.

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6 children and 2 adults are going to the circus. Children tickets are on sale,half price of adult tickets totaling $54. How much
Anon25 [30]

Answer:

Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

Step-by-step explanation:

Given:

Number of adults = 2

Number of Children = 6

Total Amount of tickets sold = $54.

We need to find the price of one children's ticket and one adult ticket.

Solution:

Let the Cost of 1 adult ticket be 'x'.

Now Given:

Children tickets are on sale,half price of adult tickets.

Cost of 1 Children ticket = \frac{1}{2}x

Total Amount is equal to Number of adults multiplied by Cost of adult ticket plus Number of Children multiplied by Cost of Children ticket.

Framing in equation for we get;

2x+\frac{1}{2}x\times 6=54\\\\2x+3x=54\\\\5x=54\\\\x=\frac{54}{5} = \$10.8

Cost of 1 adult ticket = $10.8

Cost of 1 children ticket = \frac{x}{2}=\frac{10.8}{2} = \$5.4

Hence Price of 1 adult ticket is <u>$10.8</u> and Price of 1 children ticket is <u>$5.4</u>.

7 0
4 years ago
What is - 3/5 x = 15
Keith_Richards [23]

Answer:

X = 25 because 25 · 3/5, you will get 15

5 0
4 years ago
Calculate a four-day moving average for the price of the stock for the end of day 7. day 1 - 62.00; day 2 - 56.00; day 3 - 50.00
Aneli [31]

At day 7, the four-day moving average for the price of the stock would be $58.25.

<h3>What is the four-day moving average at day 7?</h3>

This can be found as:

= (Day 7 price + Day 6 + Day 5 + Day 4) / Number of days

Solving gives:

= (59 + 55 + 59 + 60) / 4

= 233 / 4

= $58.25

Find out more on moving averages at brainly.com/question/15188858.

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8 0
2 years ago
Simplify 5x(3x^2+2x-3)
Tcecarenko [31]

Answer:

15x^3 +10x^2 - 15x

Step-by-step explanation:

Hello!

Use the distributive property and multiply like terms.

<h3>Simplify</h3>
  • 5x(3x^2 + 3x - 3)
  • 5x(3x^2) + 5x(2x) + 5x(-3)
  • 15x^3 +10x^2 - 15x

The simplified form is 15x^3 +10x^2 - 15x.

4 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Mila [183]

Answer:

m\angle H = 44.4\°.

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7    ....Side opposite to angle H

GH = 10  .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

sin \ H = \frac{Oppsite\  side\  to\  \angle H}{Hypotenuse}

Substituting the values we get;

sin\ H = \frac{7}{10} = 0.7

Now taking sin^{-1} we get;

\angle H = sin^{-1}\ 0.7 = 44.427

rounding to nearest tenth we get.

m\angle H = 44.4\°.

Hence m\angle H = 44.4\°.

6 0
3 years ago
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