SOLUTION
Given B is the midpoint of AC ABBC 1 and C is the midpoint of BD BCCD2 ie on adding 1 and 2 ART We get ABBCBCCD hence ABCD hence proved
Answer:
SO what it is is
Step-by-step explanation:
its 10 and 15/355555
<u>Answer:</u>
<u>1. A. You allow the passenger to board his flight when the passenger has a weapon.</u>
<u>2. B. You select the passenger for further inspection when the passenger has no weapon.</u>
<u>Explanation:</u>
1. Remember, a Type I error in simple words means that the assumption "the passenger has a weapon" (null hypothesis) is <em>actually true,</em> but the airport security screener <em>incorrectly concluded it is false. </em>In other words, he assumed the passenger had no weapon and allowed the passenger to board his flight <u>when he actually did have one.</u>
<em>2. While, </em><em>a </em><em>Type II error </em><em>means that </em>the assumption "the passenger has a weapon" (null hypothesis) is <em>actually false, </em>but the airport security screener <em>incorrectly concluded it is true. </em>In other words, he assumed the passenger had a weapon and selected the passenger for further inspection <u>when he actually didn't have one.</u>
You would multiply the like (or similar) terms together.
2*4= 8
-5i*7i= -35i
The correct answer is "A".
I hope this helped you.
Brainliest answer is always appreciated.
Answer:
- 11040 m³
- k ≈ 0.33
- V = (1/3)Bh
Step-by-step explanation:
The given relation is ...
V = kBh . . . . . for some base area B, height h, and constant of variation k
We are given length and width of the base so we presume it is a rectangle.
B = l·w = 8·11 = 88 . . . . square meters
The given volume tells us the value of k:
1144 = k(88)(39) . . . . . . cubic meters
1144/3432 = k = 1/3 ≈ 0.33
The value of k is about 0.33.
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Then the volume of the larger pyramid is ...
V = (1/3)(15 m)(46 m)(48 m) = 11,040 m³
The general relationship is ...
V = 1/3Bh