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AleksandrR [38]
3 years ago
8

If f (1) =4 and f(4)= f (n-1)-4 then find the value of f(4)

Mathematics
1 answer:
GaryK [48]3 years ago
3 0

f(1) = 4 is given

f(n) = f(n-1)-4 is the recursive step or rule

f(2) = f(2-1)-4 ... replace n with 2

f(2) = f(1) - 4

f(2) = 4-4 ... replace f(1) with 4

f(2) = 0

----------

Repeat for n = 3

f(n) = f(n-1)-4

f(3) = f(3-1)-4

f(3) = f(2) - 4

f(3) = 0 - 4 .... replace f(2) with 0, which is from f(2) = 0 found earlier

f(3) = -4

---------

Repeat for n = 4

f(n) = f(n-1)-4

f(4) = f(4-1)-4

f(4) = f(3) - 4

f(4) = -4-4 ... plug in f(3) = -4

f(4) = -8

<h3>Answer is   -8</h3>
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y = ax² + bx + c

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For point (3, -10)

-10 = a(3)² + 3b + c

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For point (4, -16)

-16 = a(4)² + 4b + c

16a + 4b + c = -16 ------(2)

For point (5, -24)

-24 = a(5)² + 5b + c

25a + 5b + c = -24 -----(3)

Equation (1) - equation (2)

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-7a - b = 6

7a + b = -6 ------(4)

Equation (2) - equation (3)

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-9a - b = 8

9a + b = -8 -------(5)

Equation (4) - Equation (5)

(7a + b) - (9a + b) = -6 + 8

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From equation (4),

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b = -6 + 7

b = 1

From equation (1)

9(-1) + 3(1) + c = -10

-9 + 3 + c = -10

c = -10 + 6

c = -4

Therefore, the value of constant term c is (-4).

5 0
3 years ago
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