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Leviafan [203]
3 years ago
10

Every $4,000 spent on cable TV will reach 160 fans while every $2,750 spent on radio ad will reach 125 fans. A stadium has estab

lished a goal of reaching 200,000 fans with it's advertisement. It has an advertising budget of $3 million. Which advertising option should the stadium use to meet the goal?
Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

Neither of the two advertising options meet the goal.

Step-by-step explanation:

Every $4,000 spent on cable TV will reach 160 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by \frac{4000 \times 200000}{160} = 5000000 dollars i.e. $5 million which is greater than the budget of $3 million.

Now, every $2,750 spent on radio ads will reach 125 fans.

Therefore, the goal of reaching 200000 fans will be fulfilled by \frac{2750 \times 200000}{125} = 4500000 dollars i.e. $4.5 million which is again greater than the budget of $3 million.

Therefore, neither of the two advertising options meet the goal. (Answer)

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dem82 [27]

Answer: 226.9 square in.

Step-by-step explanation: Remember that the formula for the area of a circle is (pi)r^2. Since the diameter is 17, you divide that by 2 to get your radius: 8.5. Now, put it into the formula to get your answer. (226.865 is the original, 226.9 is rounded to tenths)

5 0
3 years ago
Farah rolls a fair dice and flips a fair coin. What is the probability of obtaining a 5 and a head? Give your answer in its simp
yan [13]

Answer:

1/12

Step-by-step explanation:

1 in 6 probablity on the dice and 1/2 probablity on the coin. multiply 6 and 2 = 12

1/12 probablity

i think this is the right answer but im not 100 percent sure

6 0
3 years ago
Plz help ill give 17 points thx
Blizzard [7]

Answer:

1:6 = 7:42

Step-by-step explanation:

6 0
3 years ago
Activity
hodyreva [135]

Answer:

The answers to each part are:

Part A.

  • <u>The quantity of apples is one-third of the quantity of grapes</u>.

Part B.

  • <u>The quantity of apples is a quarter of the quantity of strawberries</u>.

Part C.

  • <u>The number of cherries is two-elevenths of the total fruit</u>.

Step-by-step explanation:

To identify the answer in each case, you must remember that all the parts are equal, then:

Part A.

The parts of apples are 1 and the parts grapes are 3, so if you divide the first quantity with the second quantity you obtain:

  • 1 / 3 = 1/3 (one-third)

So, <u>the quantity of apples is one-third of the quantity of grapes</u> or the quantity of apples is three times smaller than the quantity of grapes.

Part B.

The parts of apples are 1 and the parts of strawberries are 4, then you must divide the first quantity with the second quantity:

  • 1 / 4 = 1/4 (a quarter)

In this case, <u>the quantity of apples is a quarter of the quantity of strawberries</u> or the quantity of apples is four times smaller than the quantity of strawberries.

Part C.

First, you must add all the part of fruit:

  • <em>1 part apple</em>
  • <em>1 part orange</em>
  • <em>4 parts strawberry</em>
  • <em>2 parts cherry </em>
  • <em>3 parts grape</em>

The total of fruits is 11 parts, taking into account the quantity of cherries is 2, now you can divide the number of cherries with the total parts of fruit:

  • 2 / 11 = 2/11 (two-elevenths)

Now, you can see <u>the number of cherries is two-elevenths of the total fruit</u>.

3 0
3 years ago
Evaluate the expression \dfrac{7^2}{x^2-2} x 2 −2 7 2 ​ start fraction, 7, squared, divided by, x, squared, minus, 2, end fracti
sertanlavr [38]

Answer:

7

Step-by-step explanation:

We want to evaluate the fraction below for x = 3. We will put the value of x to be 3:

\dfrac{7^2}{x^2-2}\\\\= \dfrac{7^2}{3^2-2}\\\\= \dfrac{49}{9-2}\\\\= \dfrac{49}{7} = 7

The answer is 7.

3 0
4 years ago
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