3 / (1/8) = 3 × (8/1) = 24
There needs to be 24 students on a team.
3(-2) -(1) -3(-2)
= -6 -1 +6 = -1
11*13=143
11+13=24
The sum of the two consecutive odd integers is 24
<u>Use the previous given coordinates to solve for B.
Y=mx+b,
(3)=1/6(12)+b
3= 2+b
3-2=b
1=b
</u>
