We want to get a statement about polynomials equivalent to the one given for integers.
We will get:<em> "A polynomial times a polynomial produces a polynomial"</em>
<h3>
How to get the statement?</h3>
First, we need to read the given statement for integers, it is:
"an integer times an integer produces an integer"
Now let's see if we can extrapolate this to polynomials, suppose we have two polynomials of degree n and m.
![p(x) = a_m*x^m + ... + a_0\\q(x) = b_n*x^n + ... + b_0](https://tex.z-dn.net/?f=p%28x%29%20%3D%20a_m%2Ax%5Em%20%2B%20...%20%2B%20a_0%5C%5Cq%28x%29%20%3D%20b_n%2Ax%5En%20%2B%20...%20%2B%20b_0)
If we take the product of these two we will get another polynomial:
![p(x)*q(x) = (a_m*b_n)*x^{n + m} + ... + a_0*b_0](https://tex.z-dn.net/?f=p%28x%29%2Aq%28x%29%20%3D%20%28a_m%2Ab_n%29%2Ax%5E%7Bn%20%2B%20m%7D%20%2B%20...%20%2B%20a_0%2Ab_0)
Thus, we can conclude that the<em> product of two polynomials gives another polynomial</em>, then the statement will be:
<em>"A polynomial times another polynomial produces a polynomial"</em>
<em />
If you want to learn more about polynomials you can read:
brainly.com/question/4142886
Answer:
imma sayyyy hmmmmmmmmmmmmmmmmmmmmmmmmmmmmm b
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
The given equation is
![3z-19=173](https://tex.z-dn.net/?f=3z-19%3D173)
First, we add 19 on each side
![\begin{gathered} 3z-19+19=173+19 \\ 3z=192 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%203z-19%2B19%3D173%2B19%20%5C%5C%203z%3D192%20%5Cend%7Bgathered%7D)
Then, we divide the equation by 3
![\begin{gathered} \frac{3z}{3}=\frac{192}{3} \\ z=64 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B3z%7D%7B3%7D%3D%5Cfrac%7B192%7D%7B3%7D%20%5C%5C%20z%3D64%20%5Cend%7Bgathered%7D)
<h2>Hence, z is equal to 64.</h2>