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gregori [183]
3 years ago
7

HELP NOW PLLLLLZZZZZ!

Mathematics
2 answers:
dedylja [7]3 years ago
6 0

Answer: The car would need 0.3 gallons of fuel to travel 20km.

Step-by-step explanation: 40mile x 1.6km = 64km

                                           1 gallon     1 mile    1 gallon

20km ÷ 64km = 0.3125

Nostrana [21]3 years ago
6 0

Answer:

In 0.3 gallon of fuel, the car will travel 20 km.

A is the correct option.

Step-by-step explanation:

We have been given that in 1 gallon of fuel the car can travel 40 miles.

Now, 1 mile = 1.6 km.

Hence, in 1 gallon the car travel 40×1.6 = 64 km

Let the car will consume x gallons of fuel to travel 20 km.

Thus, we have the equation

\frac{1}{64}=\frac{x}{20}

ON solving for x

x=\frac{20}{64}\\\\x=0.3

Therefore, in 0.3 gallon of fuel, the car will travel 20 km.

A is the correct option.

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Jorge's rectangular garden was 17 feet long and had a perimeter of 54 feet. He made his garden 5 feet longer. What is the area o
antiseptic1488 [7]
Total= 54 feet
17+ 5 = 22 feet
Area= 22 feet bruh!
5 0
3 years ago
Read 2 more answers
What's the answer of {2^3+[4*(10-6)]}/3
Evgesh-ka [11]
Do 2^3 first. It is isolated on one side of a set of the + sign.
{8 + [4*(10 - 6)]} / 3 Next do the innermost 
{8 + [4*4]} / 3 Do what's in the square brackets.
{8 + 16} / 3
24/3 Divide by 3
The answer is 8

8 <<<< answer.
4 0
3 years ago
a survey conducted in a school showed that 65% of the students walked to school. The remaining students took buses to school. Th
Feliz [49]
I fear that there is an error copying your assignment.  
65% of the students walked.  Are all of the other students on buses?  Are there both public buses AND private buses?
Assuming that you need to know BOTH kinds of buses, try this:

65% of the students walked, so since 100% - 65% = 35% then this means that 35% of the students were on buses.
Since we know that there are 360 more walkers than bus riders, then one equation we know is:  65% of S = 360 + 35% of S  (let S = total # of students)
              .65 S     = 360 + .35 S
           <u> - .35 S   </u>  =     <u>   - .35 S</u>      Subtract .35 S from both sides
             <u> .30  S   </u> = <u> 360</u>                 Divide both sides by .30 (or .3)
                .30           .30
                      S   =  1,200  so we know that this is the total number of students, but that is not what was asked.  
They want to know how many are on buses and specifically how many are on public buses, if I read this correctly.
   Since the walkers = 65% of 1,2000 and we know of means TIMES, then
                                  .65 (1,200) =  780 walkers
 1,200 total students minus 780 walkers = 420 bus riders

Now, if there is not a misprint and we really have to figure out the public bus riders as compared to the private bus riders, then remember the ratio from above in the question:   4 bus: 3 public buses
Now if I read this right, that means that 3/4ths of the bus riders were on public buses
so 3/4 of 420 means 3/4 times 420  = 3 times 105 = 315 public bus riders (which coincidentally leaves 105 private bus riders, but since they are private we don't know much about them.  Ha-Ha..... I made a lame joke.)

So your answer is 315 public bus riders



5 0
3 years ago
Read 2 more answers
Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:
Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side  that is  ().

Therefore the required interval form is

[-6,-2)U(-2,3)

As we see that () are used with -2 and 3 . And that's the required interval form .

5 0
3 years ago
A blue container weighs 4 x 103
NemiM [27]

Answer:

208

Step-by-step explanation:

First let's find out what each container weighs..

Blue = 4 x 103 = 412

Red = 102 x 2 = 204

Now, Let subtract Blue container by Red Container..

412-204=208

Hence, the blue container weighs 208 more than the red container.

8 0
2 years ago
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