Answer:
?
Step-by-step explanation:
The answer would be A because you would use the Pythagorean theorem which is a^2+b^2=c^2. Therefore it would be 36+64=100, which is correct. If you wanted to be sure do it for the rest and none of them will work. Hope this helps!
Find the derivative of the curve to find the line slope at the given point
sqrt(xy) + 4 dy/dx = 39
0.5(xy)^(-0.5) * (y + x dy/dx) + 4dy/dx= 0
No need to amplify simply plug in the given point ( 1,9)
0.5 ( 1 * 9)^(-0.5)* ( 9 + dy/dx) + 4dy/dx = 0
Solve for dy/dx
1/6( 9 + dy/dx) = -4dy/dx
9 + dy/dx = -24 dy/dx
-25dy/dx = 9
dy/dx = -9/25
as your question implies , you know the rest of the steps.
Answer:
-5/2(3x+4)<6-3x (multiply with -5/2)
-15/2x-10<6-3x (multiply with 2)
-15x-20<12-6x (change sides)
-15x+6x<12+20
-9x<12+20
-9x<32
x>-32/9
Hope this will help u :)
Answer:
1. 18 (sqrt21 - sqrt2a)
2. 3
3. x^m/n
4. (5x^4√10)/(√2x)
5. x = -2 or -6
6. x = 30
Step-by-step explanation:
Number 1
3^3sqrt21 - 6^3sqrt2a
3 * 6 * sqrt21 - sqrt2a
18 (sqrt21 - sqrt2a)
Number 2
3^1/2 * 3^1/2 =
3^1/2+1/2 =
3^1 =
3
Number 3
^nsqrtx^m =
x^m/n
Number 4
(√250x^16)/(√2x) =
(√25 * 10 * x^16)/√(2x )=
(5x^4√10)/(√2x)
Number 5
√2x + 13 - 5 = x
√2x + 13 = x + 5
square both side to take away the sqrt sign
(√2x + 13)^2 = (x + 5)^2
expand the equation on the RHS
2x + 13 = x(x+5) + 5(x+5)
2x+13 = x^2 + 10x +25
substract 13 from both sides
2x = x^s + 10x +12
subtract 2x from both sides
0 = x^2 +8x + 12
Factorize equation
x^2 + 6x +2x + 12 = 0
x(x+6) + 2(x+6) = 0
(x+2)(x+6) = 0
x = -2 or -6
Number 6
3 ^5sqrt(x+2)^3 + 3 = 27
subtract 3 from both sides
3 ^5sqrt(x+2)^3 = 27 - 3
3 ^5sqrt(x+2)^3 = 24
divide through by 3
^5sqrt(x+2)^3 = 8
square both sides by 5 to take away the 5th root sign
(x+2)^3 = (8)^5
(x+2)^3 = 32,768
take the cube root of both sides to take away the ^3
x+2 = ^3sqrt 32,768
x+2 = 32
x = 32 - 2
x = 30
