Jase wrote the prime factorization of 99. Which expressions could he have written?

Mathematics

1 answer:

Inessa05 [86]3 years ago

4 0

Answer:

A and d is the correct answer

Step-by-step explanation:

A and d is matter fact correct answer

You might be interested in

What is the answer to this word problem??

AveGali [126]

Let’s use m for months
So,
1st service
10m + 20

1. 10 + 20 =30
2. 10x2=20+20=40
3.10x3=30+20=50
4.10x4=40+20=60
5.10x5=50+20=70

2nd service
11m + 15

1. 11+15=26
2. 11x2=22+15=37
3 11x3=33+15=48
4.11x4=44+15=59
5.11x5=55+15=70

So, the 5th month the services cost the same

Hope this helps! ;)

7 0

3 years ago

Ron is 5 years older than twice his cousins pats age. The sum of their ages is less than 35. What is the grates age pat could be

Anestetic [448]

The answer is 7 because if you multiply 7 with 5 than it will equal 35

Hope it helps

7 0

3 years ago

The College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with

likoan [24]

Answer:

Percentage of students who scored greater than 700 = 97.72%

Step-by-step explanation:

We are given that the College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with a mean of 500 and a standard deviation of 100.

Let X = percentage of students who scored greater than 700.

Since, X ~ N( $\mu, \sigma^{2}$ )

The z probability is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1) where, $\mu$ = 500 and $\sigma$ = 100

So, P(percentage of students who scored greater than 700) = P(X > 700)

P(X > 700) = P( $\frac{X-\mu}{\sigma}$ < $\frac{700-500}{100}$ ) = P(Z < 2) = 0.97725 or 97.72% Therefore, percentage of students who scored greater than 700 is 97.72%.