Answer:
216.9
Step-by-step explanation:
Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
__
<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
__
<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
Answer:
15+18
Step-by-step explanation:
3(5)+3(6)=15+18
First you must make sure all measurements are in the same value: You can choose either cm or km
Distance = 1,000,000 cm or 10 km
Radius = 50 cm or 0.0005 km
Distance/(2πR)
1,000,000/(2π*50)
1,000,000/314.059…….
Approx = 3183.1 Rotations
Answer: 1-27 2-8 3-9 4-32
Step-by-step explanation:
