All categories

3 years ago

Convert each measure to radians and state answer in terms of pi. a.) 40(degrees) b.) -570(degrees)

1 answer:

7 0

360 degrees=2pi radians

therefor set up a ratio and proportiopn

a.
360/2pi=40/x
times 2pix both sides
360x=80pi
divide both sides by 360
x=(2pi)/9 radians

b.
360/2pi=-570/x
times 2pix both sides
360x=-1140pi
divide boh sides by 360
x=-(19pi)/6 radians

a. (9pi)/2 radians
b. (-19pi)/6 radians

You might be interested in

HELP PLEASE 14 POINTS

hram777 [196]

Answer:

To my knowledge of congruency, I would say the answer is A,

Step-by-step explanation:

Hope this helped!!!

8 0

3 years ago

Which is the coefficient in the algebraic expression 12x + z^4 ?

love history [14]

I think the coefficient is the 12, before the variable

8 0

3 years ago

Read 2 more answers

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago

2×-6=12

Svet_ta [14]

Answer:

2 multiply by six is 12

Step-by-step explanation:

this answer is not correct

the answer would be -12 as the biggest no. is 6 and it contains - sign

hope it helps you pls mark me as brainlest

if not possible the just thank and vote

7 0

3 years ago

An icicle has a volume of 3769.91 mm if this icicle Drips at a rate of 75 mm/min How long will it take the icicles completely me

kvasek [131]

Answer:

The answer is 3,019.92 cubic millimeter

Step-by-step explanation:

take 375 plus 375 to get 750

then 3769.91 - 750 to get the 3,019.92

3 0

3 years ago

Read 2 more answers