M1Q13.) Find the relative frequency of the 2nd class to the nearest tenth of a percent.
2 answers:
Answer:
9.1%
Step-by-step explanation:
The total number of observations is 33. The number in the second class is 3, so the relative frequency is ...
3/33 × 100% = (100/11)% ≈ 9.1%
Add everything in the frequency column.
= 33
Take class two (3).
Solution:
3/33 * 100%
1/11 * 100%
100/11%
9.1%
Best of Luck!
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