M1Q13.) Find the relative frequency of the 2nd class to the nearest tenth of a percent.

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

9.1%

Step-by-step explanation:

The total number of observations is 33. The number in the second class is 3, so the relative frequency is ...

3/33 × 100% = (100/11)% ≈ 9.1%

posledela3 years ago

4 0

Add everything in the frequency column.

= 33

Take class two (3).

Solution:

3/33 * 100%

1/11 * 100%

100/11%

9.1%

Best of Luck!

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