3 years ago

What is the value of the x variable in the solution to the following system of equations?

1 answer:

8 0

Its A. x=4

procedure: 3*equation1 - 2*equation2 ⇒ x=4

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Mazyrski [523]

we have

$x^{2}-8x=3$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2}-8x+16=3+16$

$x^{2}-8x+16=19$

Rewrite as perfect squares

$(x-4)^{2}=19$

$(x-4)^{2}=19\\ (x-4)=(+/-)\sqrt{19} \\ \\ x1=4+\sqrt{19} =8.359\\ x2=4-\sqrt{19} =-0.359$

therefore

the answer is

$x1=4+\sqrt{19} =8.359\\x2=4-\sqrt{19} =-0.359$

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3 years ago