Question

A rope is cut into three pleces. The lengths are given as 2ab(a - b), 3^2(a + 2b), and b^2 (2a - b).

Answer 1

Answer:

Step-by-step explanation:

Hello, please consider the following.

$2ab(a-b)+3a^2(a+2b)+b^2(2a-b)\\\\=2a^2b-2ab^2+3a^3+6a^2b+2ab^2-b^3\\\\=\boxed{3a^3-b^3+8a^2b}$

For a = 2, b = 3 the total is

$3\cdot 2^3-3^3+8\cdot 2^2 \cdot 3\\\\=3*8-27+96\\\\=24-27+96\\\\=\boxed{93}$

Thank you

Answer 2

Its very confusing so sry