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zavuch27 [327]
3 years ago
12

A rope is cut into three pleces. The lengths are given as 2ab(a - b), 3^2(a + 2b), and b^2 (2a - b).

Mathematics
2 answers:
gladu [14]3 years ago
6 0

Answer:

Step-by-step explanation:

Hello, please consider the following.

2ab(a-b)+3a^2(a+2b)+b^2(2a-b)\\\\=2a^2b-2ab^2+3a^3+6a^2b+2ab^2-b^3\\\\=\boxed{3a^3-b^3+8a^2b}

For a = 2, b = 3 the total is

3\cdot 2^3-3^3+8\cdot 2^2 \cdot 3\\\\=3*8-27+96\\\\=24-27+96\\\\=\boxed{93}

Thank you

pickupchik [31]3 years ago
5 0

Its very confusing so sry

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