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tia_tia [17]
3 years ago
12

Which of the following is a list of equivalent numbers?

Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0

Answer:

C. 12.5,114,125

Step-by-step explanation:

:3:3:3:3::33

sergiy2304 [10]3 years ago
5 0

Answer:

D

Step-by-step explanation:

We have to find the list of equivalent numbers

A.1.25,1\frac{1}{4},12.5%

1\frac{1}{4}=\frac{5}{4}=1.25

12.5%=\frac{125}{1000}=0.125

Given numbers are not equivalent

Hence, option A is false.

B.0.125,\frac{1}{4},12.5%

\frac{1}{4}=0.25

12.5%=\frac{125}{1000}=0.125

Given numbers are not equivalent.

Hence, option B is false.

C.12.5,1\frac{2}{12},125%

1\frac{2}{12}=\frac{14}{12}=1.167

125%=\frac{125}{100}=1.25

Given numbers are not equivalent.

Hence, option C is false.

D.1.25,1\frac{1}{4},125%

1\frac{1}{4}=\frac{5}{4}=1.25

125%=\frac{125}{100}=1.25

Given numbers are equal.

Hence, option D is true.

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5 0
3 years ago
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The length of a rectangular poster is 9 more inches than two times its width. The area of the poster is 161 square inches. Solve
irinina [24]

Answer:

<u>Width = 7 inches</u>

<u>Length = 23 inches</u>

Step-by-step explanation:

Let :

  • length = 2x + 9
  • width = x

Equating to area :

  • (2x + 9)(x) = 161
  • 2x² + 9x = 161
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Dimensions are :

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8 0
2 years ago
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A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co
Ira Lisetskai [31]

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

df = 103-1 = 102

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have T = 2.63.

Now, we need to find the standard deviation of the sample. That is:

s = \frac{0.56}{\sqrt{103}} = 0.055

Now, we multiply T and s

M = T*s = 2.63*0.055 = 0.145

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

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Answer:

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