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3 years ago

Classify a triangle with angle measurements of 40∘, 30∘,110∘

Mathematics

1 answer:

shepuryov [24]3 years ago

4 0

Step-by-step explanation:

scalene triangle

scalene triangle is where all the angles are different due to the sides of the triangle different in length

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Evaluate 3y^2-5y-6 when y =2

tester [92]

Answer:

the answer would be -4

Step-by-step explanation:

just replace the variable y with two in the expression and solve

3(2)^2-5*2-6

7 0

3 years ago

A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation: A=8

jonny [76]

Answer:

In 1981 was the building worth double it’s value.

Step-by-step explanation:

Given : A townhouse in San Francisco was purchased for $80,000 in 1975. The appreciation of the building is modeled by the equation : $A=80000(1.12)^t$ , where t represents time in years.

To find : In what year was the building worth double it’s value in 1975?

Solution :

The amount is $80,000.

The building worth double it’s value in 1975.

i.e. amount became A=2(80000).

Substitute in the model,

$2(80000)=80000(1.12)^t$

$(1.12)^t=\frac{2(80000)}{80000}$

$(1.12)^t=2$

Taking log both side,

$t\log (1.12)=\log 2$

$t=\frac{\log 2}{\log (1.12)}$

$t=6.11$

i.e. Approx in 6 years.

So, 1975+6=1981

Therefore, in 1981 was the building worth double it’s value.

4 0

4 years ago

This is the attached diagram to 5

Ber [7]

The problem statement tells you ∠MLK is 61°, so ∠LMK = 180° -68° -61° = 51°. Since a tangent is always perpendicular to a radius, triangles LJM and LJK are right triangles.

Trigonometry tells you ...
tangent = opposite / adjacent
so you can write two relations involving LJ.
tan(51°) = LJ/JM
tan(68°) = LJ/JK
The second equation can be used to write an expression for LJ that can be substituted into the first equation.
LJ = JK*tan(68°) = 3*tan(68°)
Substituting, we have
tan(51°) = 3*tan(68°)/JM
Multiplying by JM/tan(51°), we get
JM = 3*tan(68°)/tan(51°)
JM ≈ 6.01

The radius of circle M is about 6.01.

6 0

3 years ago

5x y>_10 x y<_6 x 4y>_12 x>_0 y>_0 minimum for c=10,000x + 20,000y

Serga [27]

We are given inequalities : 5x+y=>10

x+y<=6

x+4y=>12

x=>0

y=>0 .

Let us graph it first and the find the coordinate of the vertices of feasible region.

Coordinates of the feasible region are (1,5) , (1.474, 2.632) and (4,2).

Now, we need to plug those cordinates (1,5) , (1.474, 2.632) and (4,2) in the given function c=10,000x + 20,000y.

Let us plug those points one by one.

For (1,5)

c=10,000x + 20,000y = 10,000(1)+ 20,000(5)= 10,000+ 100,000 = 110,000.

For (1.474, 2.632)

C = 10,000(1.474)+ 20,000(2.632) = 67,380.

For (4,2)

C = 10,000(4)+ 20,000(2) = 80,000.

We got the minimum value 67,380 for (1.474, 2.632) coordinate.

Therefore, minimum for given function C=10,000x + 20,000y is 67,380.

5 0

4 years ago

What it the nearest intger to cube root 25

yulyashka [42]

Since we know the cube of 2 is 8 and the cube of 3 is 27, we know it must be between these two numbers, and since 25 is much closer to 27 than it is to 8, we can say the closest integer is 3.

3 0

3 years ago