Ask question

Ask question

All categories

2 years ago

11

There are 10 girls for every 12 boys. If there are 50 girls,

2 answers:

Mice21 [21]2 years ago

8 0

We know that 10 x ❺ = 50

So we have to do 12 x ❺ = 60

So the answer is a) 60

Katyanochek1 [597]2 years ago

3 0

Answer: A

why does this keep changing to C????

Step-by-step explanation:

10x5 since there are 50 girls

so we would need to multiply 12 by the same number, so the answer is 60.

You might be interested in

Here are the fuel efficiencies (in mpg) of 12 new cars . 28, 14, 48, 22, 14, 18, 52, 36, 32, 20, 12, 55 What is the percentage o

SSSSS [86.1K]

25% assuming you don’t count the car with 18 mpg fuel efficiency.

if you add the amount of cars up that have less than 18 mpg and then divide it by the total number (12) you will get a decimal (0.25) to find the percent multiply the decimal by 100

5 0

3 years ago

Read 2 more answers

In a art class, there are 32 pens to 40 brushes what is the ratio of pens to brushes written as a fraction in simplest form ?

kolezko [41]

32/40 is the fraction to 32:40 and if u simplify it, it would be 4/5

4 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Help this is really hard

Agata [3.3K]

(2^8 *3^-5* 6^0)^-2 * ((3^-2)/(2^3))^4 * 2^28

anything to the 0 power is 1

(2^8 *3^-5* 1)^-2 * ((3^-2)/(2^3))^4 * 2^28

using the power of power property to take the power inside

(2^(8*-2) *3^(-5* -2) * (3^-2*4)/(2^3*4) * 2^28

simplify

2^ -16 * 3^10 * 3^-8 /2*12 * 2^28

get rid of the division by making the exponent negative

2^-16 * 3^10 * 3^-8 *2*-12 * 2^28

combine exponents with like bases

2^(-16-12+28) * 3^(10-8)

2^(0) *3^2

anything to the 0 power is 1

1*9

9

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to 3m1-m?<br> A) 2+m-1+m<br> B) 1+m<br> C) 3m-1<br> D) 3m

valkas [14]

Answer:

C

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers