Here we're interested in the circumference: C = pi*d. In this case C = 3.14*(28 inches) = 88 inches.
Now divide this 88 inches into 200 feet to get the # of revolutions ncessary to travel 200 feet.
200 feet 12 in
------------ * --------- = 2400 inches
1 1 ft
2400 inches
----------------------- = 27.2 revolutions (answer)
[ 88 inches/ rev ]
The length of the median from vertex C is equal to √17. As a median of a triangle is a line segment joining a single vertex to the midpoint of the opposite side of the triangle. In this case, the median will be from vertex C to the mid-point of the triangles side AB.<span> Thus, we can work out the length of the median from vertex C by using the Midpoint formula; M(AB) = (X</span>∨1 + X∨2) /2 ; (Y∨1 + Y∨2) /2 . Giving us the points of the midpoint of side AB, which can be plotted on the cartesian plane. to find the length of the median from vertex C, we can use the distance formula and the coordinates of the midpoint and vertex C , d = √(X∨2 - X∨1) ∧2 + (Y∨2 - Y∨1)∧2.
Answer:
H0 : μd = 0
H1 : μd ≠ 0
Test statistic = 0.6687 ;
Pvalue = 0.7482 ;
Fail to reject H0.
Step-by-step explanation:
H0 : μd = 0
H1 : μd ≠ 0
Given the data:
Before: 15 26 66 115 62 64
After: 16 24 42 80 78 73
Difference = -1 2 24 35 -18 -9
Mean difference, d ; Σd / n
d = Σx / n = ((-1) + 2 + 24 + 35 + (-18) + (-9))
d = Σx / n = 33 / 6 = 5.5
Test statistic = (d / std / sqrt(n))
std = sample standard deviation = 20.146
Test statistic = 5.5 ÷ (20.146/sqrt(6))
Test statistic = 0.6687
The Pvalue :
P(Z < 0.6687) = 0.7482
At α = 0.05
Pvalue > α ; Hence we fail to reject H0
The data does not suggest a significant mean difference in the average number of accidents after information was added to road signs.
Answer:
False
Explanation:
Zero-dimensional would be a point.
One-Dimensional would be a line.
Two-Dimensional would be a plane.
Three-Dimensional would be a shape.
7: has a value of 7 hundreds (or 700)
5: has a value of 5 tens (or 50)
6: has a value of 6 ones (or 6)
5 has a value of 50 or five tens
I believe you would draw this by drawing something that looks like place value blocks. I have attached an example of that. In the ones column, you will have 6 single blocks
