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Arlecino [84]
4 years ago
14

What do you notice about the relationship between the force strength and the size of the velocity change?

Chemistry
1 answer:
Misha Larkins [42]4 years ago
5 0

Answer:

fkv  SFHHHHHHHHHCB FSSSSZCHJjjjb .SFFHHHHHHHHC

Explanation:

What do you notice about the relationship between the force strength and the size of the velocity change?

Uuuuuuu

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The polar bear runs at a speed of 8.3 m/sec, how long will it take it to run 200<br> meters?
nirvana33 [79]

Answer:speed of 6.5 meters per second, what is the distance she covers in that time? ... backstrokes at an average speed of 8 meters per second, how long will it take ... 200m smis. 255. 7. Lauren's SUV was detected exceeding the posted speed limit ... Suppose the polar bear was running on land instead of swimming. ... V = 8.3mls.

Explanation:

8 0
3 years ago
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Anyone know this question?
Dafna11 [192]

no goodluck tho

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8 0
3 years ago
Use the heat equation to find out how many joules of energy are needed
miss Akunina [59]

Answer:

About 7.0 × 10³ J or 7.0 kJ

Explanation:

We want to determine the amount of energy needed to raise the temperature of 67 grams of water from 20°C to 45°C.

We can use the heat equation:

\displaystyle q = mC\Delta T

Where <em>C</em> is the specific heat of water.

Substitute and evaluate:

\displaystyle \begin{aligned} q & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)\left(45^\circ \text{ C}- 20.^\circ\text{ C}\right) \\ \\ & = (67\text{ g})\left(\frac{4.2\text{ J}}{\text{g-$^\circ$C}}\right)(25^\circ \text{ C}) \\ \\ & = 7.0\times 10^3 \text{ J}\end{aligned}

Recall that there are 1000 J in a kJ. Hence:

\displaystyle \begin{aligned} q & = 7.0\times 10^3 \text{ J} \cdot \frac{1\text{ kJ}}{1000\text{ J}} \\ \\ & = 7.0 \text{ kJ}\end{aligned}

In conclusion, it will take about 7.0 × 10³ J or 7.0 kJ of energy to raise the temperature of 67 grams of water from 20 °C to 45 °C.

8 0
3 years ago
How do you convert particles to moles, and mass to moles?
wariber [46]

1. mol = 77.56/100 = 0.7756 mol

2. mol = 2.55 × 10^24/6.02 × 10^23 = 4.236 mol mass = 4.236 × 74.5 = 315.582 g

3. mass = 0.0931 × 208.3 = 19.393 g

4. mol = 1.55 × 10^22/6.02 × 10^23 = 0.0257 mol

5. molecules = 0.664 × 6.02 × 10^23 = 3.997 × 10^23 molecules

6. mol = 86/242 = 0.355 mol

7. mol = 7.88 × 10^23/6.02 × 10^23 = 1.309 mol mass = 1.309 × 44 = 57.596 g

8. mass = 7.56 × 62 = 468.72 g

9. mol = 7.56/84 = 0.09 mol

10. mol = 8.55 × 10^21/6.02 × 10^23 = 0.014 mol mass = 0.014 × 58.5 = 0.819 g

recheck to ensure all answers are correct

4 0
2 years ago
How to find the solute and solvent
Salsk061 [2.6K]

the solute is the one that dissolves meaning its particles are separating into the solvent, and the solvent is the one that dissolves the other substance.

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3 years ago
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