Answer:
0.00500M of Na₂C₂O₄
Explanation:
<em>When are dissolved in 150 mL of 1.0 M H2SO4.</em>
<em />
We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:
0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄
In 0.150L:
7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =
<h3>0.00500M of Na₂C₂O₄</h3>
Answer:
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Yes the ANSWER is Correct-
On first half life the mass will be 10 gram
On second half life the mass will be 5 gram
On third half life the mass will be 2.5 gram
Answer:
The answer is TRUE!!!
Explanation:
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<h3>
Answer:</h3>
B. 2010.62 ft³
<h3>
Explanation:</h3>
<u>We are given</u>;
Dimensions of the cylinder as 10 ft × 16 ft
We are going to take;
- Height as 10 ft
- Diameter as 16 ft
We are required to calculate the volume of the cylinder
- Volume refers to the amount of space occupied by an object.
- It is calculated depending on the shape of the solid.
In this case;
Volume of a cylinder = πr²h, where r is the radius and h is the height.
Radius, r = 8 ft
Height, h = 10 ft
Therefore;
Taking π as 3.142
Volume of the cylinder = 3.142 × (8ft)² × 10 ft
= 2010.62 ft³
Thus, the volume of the cylinder is 2010.62 ft³
