<span>6b^3 (2a+7b)
</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)
</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)
</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]
Answer: </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>
Answer:
4
Step-by-step explanation:
f⁻¹(x) = x²+3, but none of that matters, since f(f⁻¹(x)) = x
78, because you have to do the inverse operation so 80/2= 40 then 40-1= 39 and 39*3 = 78
Answer: (B) -625
<u>Step-by-step explanation:</u>
Given the sequence {-500, -100, -20, -4, -0.8, ... }, we know that that the first term (a) is -500 and the ratio (r) is 
Input those values into the Sum formula:
