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sveticcg [70]
3 years ago
11

How can we make use of acids or bases to prevent growth of micro-organisms in swimming pools?

Chemistry
1 answer:
LenKa [72]3 years ago
3 0
Bases so the micro organism in pools won't spread
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Which chemical is the reducing agent in the redox reaction below?
posledela
Option (a) is correct.

A reducing agent is the one which loses electrons to other substance.

Here, Zn has oxidation number 0 in the L.H.S of the equation, but on R.H.S its oxidation number is +2 i.e. it Zn has donated two of its electrons to Fe^{2+}.

Hence, Zn is the reducing agent here. 
6 0
3 years ago
Brainiest if correctly answered in 5m
erastovalidia [21]

I will list them from alkaline with the lowest boiling point and alkaline with the highest.

1. C2H6 
2. C9H20
3. C11H24
4. C16H34
5. C20H42
6. C32H66
7. C150H302

I have taken a quiz similar to this before and can assure you this is correct and is primarily because of the number of Carbons and Hydrogens within this. More Carbons and Hydrogens causes Boiling Points to increase because of stronger bonds.

8 0
3 years ago
If the same amount of heat is suppliedto all samples of 10.0g each of aluminum iton and copper all at 15 degree celsius which sa
s2008m [1.1K]
When a substance absorbs thermal energy, it partitions some as potential and some as kinetic energy. Specific heat is an expression related to the quantity of heat a substance stores as potential energy; the remainder is absorbed as kinetic which causes the temperature to increase - recall that temperature is a measure of average kinetic energy. 
When specific heat is low, most of the energy is partitioned as kinetic energy and the substance will experience the greatest temperature change. 

So rather than calculating the change in temperature, we can simply inspect the specific heats. The one with the lowest will experience the greatest temperature change. We could also compare the specific heats: Al = .897/.385 ==> 2.3, Fe = .452/.385 = 1.2, Cu = .385/.385 = 1. We can expect Copper's temperature change to be 2.3 times larger than Aluminum's and 1.2 times larger than Iron's.
5 0
3 years ago
Consider the following reaction at constant P. Use the information here to determine the value of ΔSsurr at 355 K. Predict wheth
Elena-2011 [213]

Answer:

\Delta S_{surr} = + 0.32113\: kJ/K

Explanation:

Given: Entropy of surrounding: ΔSsurr = ?

Temperature: T= 355 K

The change in enthalpy of reaction: ΔH = -114 kJ

Pressure: P = constant

As we know, ΔH = -114 kJ ⇒ negative

Therefore, the given reaction is an exothermic reaction

Therefore, Entropy of surrounding at <em>constant pressure</em> is given by,

\Delta S_{surr} = \frac{-\Delta H}{T}

\therefore \Delta S_{surr} = -\left (\frac{-114 kJ}{355 K}  \right ) = + 0.32113\: kJ/K > 0

<u><em>In the given reaction:</em></u>

2NO(g) + O₂(g) → 2NO₂(g)

As, the number of moles of gaseous products is less than the number of moles of gaseous reactants.

\therefore \Delta S_{system} <  0

As we know, <em>for a spontaneous process, that the total entropy should be positive.</em>

\Delta S_{total} = \Delta S_{surr} + \Delta S_{system} > 0  

<u>Therefore, at the given temperature,</u>

  • if \Delta S_{surr} > \Delta S_{system} \Rightarrow \Delta S_{total} > 0 then the given reaction is spontaneous
  • if \Delta S_{surr} < \Delta S_{system} \Rightarrow \Delta S_{total} < 0 then the given reaction is non-spontaneous
6 0
4 years ago
36. What is the pH of a solution with an H3O+ concentration of 5.67 x104 M?
skad [1K]
The answer for your question is B
4 0
3 years ago
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