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alexandr402 [8]
3 years ago
7

What occurs when aqueous aluminum nitrate, A l ( N O 3 ) 3 , reacts with aqueous ammonium phosphate, ( N H 4 ) 3 P O 4

Chemistry
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

You make aluminum phosphate which is an insoluble salt, so a precipitated is formed.

Explanation:

First reagent: Al(NO₃)₃

Second reagent: (NH₄)₃PO₄

This is the reaction:

Al(NO₃)₃  (aq) +  (NH₄)₃PO₄  (aq) → AlPO₄ (s) ↓ +  NH₄NO₃ (aq)

Al³⁺ (aq)  +  PO₄⁻³ (aq)  ⇄  AlPO₄ (s) ↓     Kps

Salt from phosphate is formed.

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3 years ago
As lead chemist for a pharmaceutical manufacturing company, you need to inform the purchasing office of a supply order for the n
Veronika [31]

Answer:

<em>mass of chlorine gas required is 118 kg.</em>

Explanation:

Total mass of the drug (Cisplatin) required = 500 kg

For the drug PtCl2(NH3)2, we first find the molar mass of the compound.

The molar mass of the drug is the total of all the molar mass of the elements in the drug

molar mass of Pt (platinum) in the drug = 195.078 g/mol

molar mass of chlorine (Cl) in the drug = 2 x (35.453 g/mol) = 70.908 g/mol

molar mass of ammonia (NH3) in the drug = 2 x (17.031 g/mol) = 34.062 g/mol

Total molar mass of the drug = 195.078 g/mol + 70.908 g/mol + 34.062 g/mol = 300.048 g/mol

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6 0
3 years ago
If the pressure P applied to a gas is increased while the gas is held at a constant temperature, then the volume V of the gas wi
yuradex [85]

Answer:

For these types of questions the equation that we must take into account is that:

T = PxV (where T is the temperature, P is the pressure and V is the volume) this equation is described as we consider that this is the value N and R is 1, therefore it is not necessary to explain them now.

Explanation:

The quoted equation refers to Boyle's Law, in this law we can explain that the volume increases if the pressure decreases and if the temperature also increases, if the pressure increases and the volume decreases this means that the gas is compressing assuming that the temperature is constant

8 0
3 years ago
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A sample of 4.50 g of diatomic oxygen (O2) occupies a volume of 15.0 L at a temperature of 203 K and a pressure of 5.0 atm. What
AleksandrR [38]

Answer:

V = 0.23 Lt

Explanation:

Data: O₂ 4.50 g = 0.14 mol (considering a molecular mass of 32 g for O₂)

V₁ = 15.0 Lt , T₁ = 203 K , P₁ = 5.0 atm

V₂ = ? , T₂ = 303 K , P₂ = 15.0 atm

If we consider that this gas beahves as an ideal gas, then:

PV = nRT

V = nRT/P

V₂ = nRT₂/P₂ , where R gas constant = 0.082 Lt*atm/K*mol

V₂ = (0.14x0.082x303)/15.0 ⇒ V₂ = 0.23 Lt

Which is consistent, considering that the gas is subjected to a high pressure (from 5 atm to 15 atm), its volume should decrease (from 15 Lt to 0.23 Lt)

3 0
3 years ago
How many grams of sodium sulfide are formed if 1.80 g of hydrogen sulfide is bubbled into a solution containing 2.40 g of sodium
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The reaction of sodium sulfide with hydrogen sulfide can be shown as

H_2S + 2 NaOH = Na_2S + 2 H_2O \\ Molar mass of H_2S = 34 g /mol\\ Mole of H_2S  = mass /molar mass\\  = 1.8 /34 = 0.051 mole\\ Mole of NaOH  = 2 * 0.051 = 0.102 mole\\ Theoritical mole of NaOH = mass /molar mass\\ = 2.4 /40 = 0.06 mole

Sodium hydroxide is completely reacting and thus act as limiting reactant

Hence, mole of Na_2S required  = 0.06 /2 = 0.03 mole\\ Mass of Na_2S = 0.03 * 78 = 2.31 g

Thus, 2.31 g Na2S produced.

4 0
3 years ago
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