Answer:
A: molar ratio
Molar ratios state the proportions of reactants and products that are used and formed in a chemical reaction.
(does this belong in chemistry?)
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Melting is a process where a solid such as ice turns into liquid or water. The molecules of ice slowly moves and becomes unstable as they gain energy. As this energy builds up, kinetic energy increases and the intermolecular forces react because of this energy.Thank you for your question. Please don't hesitate to ask in Brainly your queries.
Mole fraction of Oxygen=0.381
Mole fraction of Oxygen= (range of moles of oxygen) ÷(general moles)
also, mole fraction of oxygen = (partial stress of oxygen) ÷ (total strain)
consequently , mole fraction of Oxygen= (2.31 atm)÷(2.31 atm + 3.75 atm)
= 0.381
The mole fraction may be calculated by means of dividing the variety of moles of 1 element of a solution by the entire quantity of moles of all the additives of a solution. It is cited that the sum of the mole fraction of all of the components inside the solution should be identical to 1.
Mole fraction is a unit of awareness. in the solution, the relative amount of solute and solvents are measured by way of the mole fraction and it's far represented through “X.” The mole fraction is the variety of moles of a selected aspect inside the answer divided by way of the entire range of moles in the given answer.
Mole fraction is the ratio between the moles of a constituent and the sum of moles of all ingredients in a mixture. Mass fraction is the ratio between the mass of a constituent and the full mass of a mixture.
The question is incomplete. Please read below to find the missing content.
Assuming that only the listed gases are present, what would the mole fraction of oxygen gas be for each of the following situations? A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.
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The mass of hydrazine (N₂H₄) required to produce 96 g of water (H₂O) is 85.4 g (Option C)
<h3>Balanced equation </h3>
N₂H₄ + O₂ —> N₂ + 2H₂O
Molar mass of N₂H₄ = (2×14) + (4×1) = 32 g/mol
Mass of N₂H₄ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
36 g of H₂O were produced by 32 g of N₂H₄
<h3>How to determine the mass of N₂H₄</h3>
From the balanced equation above,
36 g of H₂O were produced by 32 g of N₂H₄
Therefore,
96 g of H₂O will be produced by = (96 × 32) / 36 = 85.4 g of N₂H₄
Thus, 85.4 g of N₂H₄ is needed for the reaction
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