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Katyanochek1 [597]
3 years ago
15

Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

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Answer: C, E, F

Step-by-step explanation:

  1. Plug in the "x" and "y" values from the ordered pairs into the equation.
  2. For A: 3 = \frac{1(5)}{5} → 3 ≠ 1 → A is eliminated.
  3. For B: 5 = \frac{1(1)}{5} → 5 ≠ \frac{1}{5} → B is eliminated.
  4. For C: 2 = \frac{1(10)}{5} → 2 = 2 → C satisfies the equation.
  5. For D: 10 = \frac{1(4)}{5}→ 10 ≠ \frac{4}{5} → D is eliminated.
  6. For E: -1 = \frac{1(-5)}{5}→ -1 = -1 → E satisfies the equation.
  7. For F: 3 = \frac{1(15)}{5}→ 3 = 3 → F satisfies the equation.
  8. Therefore, C, E, and F are the answers.

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