Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was <span><span>\$43.25<span>$43.25</span></span>dollar sign, 43, point, 25</span><span>. He had to pay a </span><span><span>\$7<span>$7</span></span>dollar sign, 7</span><span> entrance fee and </span><span><span>\$1.25<span>$1.25</span></span>dollar sign, 1, point, 25</span>for every minute he was on the trampoline.<span><span>Write an equation to determine the number of minutes </span><span><span>(t)<span>(t)</span></span>left parenthesis, t, right parenthesis</span><span> that Raymond was on the trampoline.</span></span>
Answer:
1st term : 2
2nd term : 4
3rd term: 8
4th term : 16
5th term : 32
Step-by-step explanation:
Answer:
45 cm
Step-by-step explanation:
Let x represent the length of the longer leg. Then the hypotenuse is x+8 and the shorter leg is x-17. The Pythagorean theorem gives the relation between these values as ...
(x +8)^2 = x^2 +(x -17)^2
x^2 +16x +64 = 2x^2 -34x +289 . . . . eliminate parentheses
0 = x^2 -50x +225 . . . . . put in standard form
0 = (x -45)(x -5) . . . . . . . . factor
Solutions to this equation are x=5 and x=45. The value of x must be greater than 17, so the useful solution is x=45.
The length of the longer leg of the triangle is 45 cm.
Answer:
x=2√5
Step-by-step explanation:
<u>1st method:</u>
sin(30)=opposite/hypotenuse=√5/x
sin(30)x=√5
x=√5/sin(30)
x=2√5
<u>2nd method:</u>
cos(60)=adjacent/hypotenuse=√5/x
cos(60)x=√5
x=√5/cos(60)
x=2√5
<u>3rd method:</u>
This is a 30-60-90 triangle, so we can multiply the short side, √5, by 2, to get x=2√5
Answer:
14. -21 over 5, 1 over 4
Step-by-step explanation:
PQ: perform the slope formula: y2-y1 divided by x2-x1
-3 - 17 divided by 1 - (-4) = -21 divided by 5
RS: 4 - 3 divided by -5 - (-9) = 1 divided by 4