Answer:
See attached. (Note that b, d, f, h, j are cents amounts. All the other letters refer to the dollar amounts only (no cents).)
Step-by-step explanation:
The one deposit is marked with a (+) in the third column of Figure 4.16a. All the other transactions are Payment/Debit transactions. The balance on each line is the balance on the previous line less any payment and plus any deposit on that line. (It's not rocket science.)
If you actually do this in a spreadsheet, it is convenient to let the spreadsheet do the math. It is much easier to let the spreadsheet keep track of dollars and cents in the same column.
It is more difficult to break out cents to a separate column. So, your letter answers apparently need to be the dollar portion only (except as indicated above).
1.IN SOLIDS THERES NO SPACE FOR PARTICLES TO MOVE AROUND
2.LIQUID THERES A LITTLE BIT OF SPACE TO MOVE FREELY
3. GAS HAS ALL SPACES TO MOVE AROUND SINCE ITS NOT PUT TOGETHER
HOPE THIS ANSWER HELPED ALOT
Answer:
45
Step-by-step explanation:
This can be written as 5r:9g. Add 5 and 9 to get the total of 14. You can write a ratio of 9 green: (out of) 14 total = x green: (out of) 70 total. Multiply 9 and 14 by 7 to get 45:70. Therefore, if there are 70 hairbands, 45 are green.
Answer:
y = 3
x − 3
Step-by-step explanation:
Subtract 4
x from 7
x
= y = 3
x − 3
Given the distance covered and the time elapsed, Ryashkina's average walking rate is approximately 3.97 meters per second.
<h3>What was Ryashkina's average walking rate?</h3>
Rate or speed is expressed as distance walked or traveled per unit time.
R = s/t
Given the data in the question;
- Distance covered s = 10,000m
- Time elapsed t = 41 minutes 56.23 seconds
- Rate r = ?
First convert 41 minutes to seconds.
⇒ 41min = ( 41 × 60 )s = 2460sec
Now, Elapsed time t = 2460s + 56.23s = 2516.23 second
Next, we determine the rate.
R = s / t
R = 10000m / 2516.23 s
R = 3.97m/s
Given the distance covered and the time elapsed, Ryashkina's average walking rate is approximately 3.97 meters per second.
Learn more about speed here: brainly.com/question/7359669
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