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Ronch [10]
3 years ago
5

Suppose you travel at 70 mph for 520 miles. How many hours will take you to reach your destination

Mathematics
1 answer:
il63 [147K]3 years ago
3 0

Answer:

7.4

Step-by-step explanation:

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A company that manufactures guitars has a fixed cost of $100,000. It costs $100 to produce each guitar and the selling price is
miv72 [106K]

a. Write the cost function:: C(x) = 100x + 100,000 where x is number of guitars

---------------------------------

b. Write the revenue function:: R(x) = 300x where x is number of guitars

-----------------------

c. Find the profit function.

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = [ R(x) ] - [ C(x) ]

P(x) = [ 300x ] - [ 100x+100,000 ]

P(x) = 300x - 100x-100,000

P(x) = 200x - 100,000

The break even point is when the profit is 0 dollars. You don't lose any money. And you don't gain any money.

Solve 125x - 100,000 = 0

125x = 100,000

x = 800 (# of guitars made and sold)

7 0
3 years ago
D={x E Z;-4 < x < 4}
tino4ka555 [31]

Answer:

D={-3,-2,-1,0,1,2,3}

7 0
1 year ago
Write an equivalent expression 2x + 10
balu736 [363]

Answer: 2 (x+5)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The branch manager of an outlet (Store 1) of a nationwide
monitta

Answer:

1. ( 19.1416, 23.5384,)

2. (0.276348, 0.46651)

3. the sample size = 170.73 approximately 171

4. sample size = 334.07 approximately 334

5. sample of 334 should be taken by manager

Step-by-step explanation:

mean = bar x = 21.34 dollars

size of sample n = 70

standard deviation of sample = 9.22

we use t distribution as the population standard deviation is not known.

95% Confidence interval

1-α = 0.95

α = 0.05

degree of freedom = 70-1 = 69

α/2 = 0.025

using the t distribution tsble,

= 1.9949

confidence interval = 21.34+-1.9949*[\frac{9.22}{sqrt(70)}] \\

= 21.34 +- (1.9949*1.10200)

= 21.34 + 2.1984, 21.34 - 2.1984

= (23.5384, 19.1416)

the confidence interval of the mean amount spent at the supply store can be written as 19.1416<u<23.5384

2. sixe of those who only have a cat

p = 26/70 = 0.371429

at 90 % confidence interval,

1-α = 0.90

α = 0.10

we use the z table here

z(0.10/2) = Z(0.05)

= 1.645

0.371429+-1.645\sqrt} \frac{0.371429(1-0.371429)}{70}

= 0.371429 +-( 1.645 x 0.0578)

= 0.371429 + 0.095081, 0.371429 - 0.095081

= (0.276348, 0.46651)

3. sd = 10$

margin of erro,r e = 1.50$

α = 0.05

using z table

α/2 = Z0.025

= 1.96

sample size = 1.96² * 10² / 1.50²

= 3.8416 * 100/ 2.25

= 170.73

the sample size is approximately 171

d. we have 0.5 as sample proportion now

margin of error = 0.045

α = 0.10

Zα/2 = 0.05

= 1.645

sample size = 1.645²x0.5(1-0.5) / 0.045²

= 0.676506/0.002025

= 334. 07

sample size = 334

5.  sample of 334 should be taken by manager

3 0
3 years ago
Abby's score in a
mezya [45]

Answer: 5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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