Answer:
c) 5√2 cm
Step-by-step explanation:
A square with side length l has a perimeter given by the following equation:
P = 4l.
In this question:
P = 20
So the side length is:
4l = 20
l = 20/4
l = 5
Diagonal
The diagonal forms a right triangle with two sides, in which the diagonal is the hypothenuse. Applying the pytagoras theorem.




Lenght is a positive meausre, so




So the correct answer is:
c) 5√2 cm
Answer:
y = -1/10x^2 +2.5
Step-by-step explanation:
The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:
-1 -4 = -5
So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).
The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...
y = (1/(4p))(x -h) +k
y = -1/10x^2 +2.5
_____
You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.
Hmmm it's linear since it's multipling by 3 each time
Answer:
<edf=23(angles standing on common arc fe)
9514 1404 393
Answer:
17) x = 10√2
18) x = 4√6
Step-by-step explanation:
These problems rely on your knowledge of the side ratios of special triangles
45°-45°-90° triangle: 1 : 1 : √2
30°-60°-90° triangle: 1 : √3 : 2
__
17) 5 is the short side of the isosceles right triangle, so its hypotenuse is 5√2. That length is the shortest side of the 30/60/90 triangle, so its longest side is 2 times that:
x = 10√2
__
18) 8 is the longest side of the 30/60/90 triangle, so its long leg will be 8(√3)/2 = 4√3. The hypotenuse of the isosceles right triangle is √2 times that, so ...
x = (4√3)(√2)
x = 4√6