Solve using substitution x=(3y+1) and x+4y=15

Mathematics

1 answer:

natka813 [3]3 years ago

3 0

The solution is: x= 7 and y = 2

Step-by-step explanation:

Given equations are:

$x = 3y+1\ \ \ \ Eqn\ 1\\x+4y = 15\ \ \ \ Eqn\ 2$

Putting x = 3y+1 in equation 2 from equation 1

$3y+1+4y = 15\\7y+1 = 15\\$

Subtracting 1 from both sides

$7y+1-1 = 15-1\\7y = 14$

Dividing both sides by 7

$\frac{7y}{7} =\frac{14}{7}\\y = 2$

Putting y=2 in equation 1

$x = 3(2) +1\\x = 6+1\\x = 7$

Hence,

The solution is: x= 7 and y = 2

Keywords: Linear equations, substitution method

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