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3 years ago

Inverse functions

Mathematics

1 answer:

lana66690 [7]3 years ago

3 0

Answer:

f(x)= e^(2x)-4

change f(x) to y, switch _6 and y. solve for _5x_

The final function

f^(-1) (x)= ln(x+_7(8_)/(_(__)

Step-by-step explanation:

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Pls helppppplppkllllll

charle [14.2K]

Answer:

Step-by-step explanation:

The two angles add up to 90 degrees

8 0

3 years ago

Help please will mark brainliest!!!

Daniel [21]

Answer:

45°

Step-by-step explanation:

Well, compared to 90°, it looks like it's just smaller, but not too small. It couldn't be 15° degrees, or 60°, as it was probably too much. I Don't think it's 30° either, because it looked bigger than what a 30° angle would be.

Hope it helped!

~Flip

7 0

3 years ago

Answer please thanks you and explain

Alex73 [517]

Answer:

the answe is 100.53088

Step-by-step explanation:

You multiply 3.14159 or pi by the 32, which is the answer, and it gives you 100.53088

5 0

3 years ago

Sketch the solid described by x 2 + y 2 ≤ z ≤ 1. Use the Divergence Theorem to evaluate the surface integral over the boundary o

kirill115 [55]

Looks like

$\vec F(x,y,z)=y\,\vec\imath+z\,\vec\jmath+xz\,\vec k$

The solid described by $x^2+y^2\le z\le 1$ is the interior of the region bounded by the paraboloid $z=x^2+y^2$ and the plane $z=1$ . Call this region $R$ .

By the divergence theorem,

$\displaystyle\iint_{\partial R}\vec F\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F\,\mathrm dV$

The divergence is

$\mathrm{div}\vec F(x,y,z)=(y)_x+(z)_y+(xz)_z=x$

so that the surface integral reduces to

$\displaystyle\iiint_Rx\,\mathrm dV$

or in cylindrical coordinates,

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1r^2\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{0}$

4 0

3 years ago

Can someone please help me

Temka [501]

What matters is the base for the exponentiation to tell if its increasing or decreasing. Among positive numbers, smaller than 1 means decreasing, bigger than one means increasing. That's because for each increase of 1 in x we get another factor of the base. If it's bigger than 1 that's growth.

There are no negative bases here, but it's similar -- less than -1 (bigger in absolute value) grows, even though it oscillates back and fourth between positive and negative.

It's blurry but I see bases of 3, .6, .74, 1.3

3: growth

.6: decay

.74: decay

1.3: growth

6 0

4 years ago