3 years ago

What is this area please help

2 answers:

7 0

I hope this helps you

4.4+4.2/2

16+4

20

4 0

The answer is 24 brainliest pls

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alina1380 [7]

ANSWER

$\begin{gathered} center=(-3,-5) \\ r=4 \end{gathered}$

EXPLANATION

Given;

$x^2+y^2+6x+10y+18=0$

The standard equation of circle of a circle centered at (h,k) with radius r is;

$(x-h)^2+(y-k)^2=r^2$

Re-write the given equation in the standard form, we have;

$\begin{gathered} x^{2}+y^{2}+6x+10y+18=0 \\ x^{2}-6x+(\frac{6}{2})^{2}+y^{2}+10y+(\frac{10}{2})^{2}=-18+9+25 \\ (x-3)^2+(y-5)^2=4^2 \end{gathered}$

Hence, h=-3, k=-5, radius is 4

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2 years ago