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omeli [17]
4 years ago
7

Write each of the equations below in standard form (i.e. y = ax^2+bx+c y=ax ​2 ​​ +bx+c):

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
5 0
C . Is the answer
Hope it helps
You might be interested in
2x(x+4)+7+=(x+8)+ 2x(x+1)+12=
Katena32 [7]

Answer:

x=2.600

Step-by-step explanation:

2x(x+4)+7+=(x+8)+ 2x(x+1)+12

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

  ->        2*x*(x+4)+7+-((x+8)+2*x*(x+1)+12)=0

-> ((2x•(x+4))+7)-(((x+8)+2x•(x+1))+12)  = 0

->  (2x • (x + 4) +  7) -  (2x2 + 3x + 20)  = 0

->  5x - 13  = 0

-> Add  13  to both sides of the equation :  

                     5x = 13

Divide both sides of the equation by 5:

                    x = 13/5 = 2.600

Please mark as brainliest

8 0
3 years ago
The point P( 0.5 , 10 ) lies on the curve y = 5 / x . Let Q be the point (x, 5 / x ) . a.) Find the slope of the secant line PQ
zalisa [80]

Answer:

Based on the results  it is expected that the slope of the tangent line at the point (0.5,10) is -20.

Step-by-step explanation:

To see that compute, the slopes for the given points as follows:

1. For x=0.6 we have:

m=\dfrac{(5/0.6)-10}{0.6-0.5}=-16.66

2. For x=0.51 we have:

m=\dfrac{(5/0.51)-10}{0.51-0.5}=-19.60

3. For x=0.4 we have:

m=\dfrac{(5/0.4)-10}{0.4-0.5}=-25.00

4. For x=0.49 we have:

m=\dfrac{(5/0.49)-10}{0.49-0.5}=-20.40

So, we observe that the slope of the tangent line at (0.5, 10) is close to the value -20.

The graph shown below is useful to see the secant lines that approximates the tangent line.

7 0
4 years ago
Solve for 2. Write the smaller solution first, and the larger solution s
ZanzabumX [31]

Answer:

4(x^2 +10 +21)

4(x+3)(x+7) = 0

Smaller

4(x+7) = 0

4x +28 = 0

4x = -28

x = -28/4

x = -7

Larger

4(x+3) = 0

4x + 12 = 0

4x =-12

x = -12 / 4

x = -3

Step-by-step explanation:

4 0
3 years ago
Put these fractions in order from least to greatest. <br><br>2/3<br>6/8<br>1/5​
Julli [10]

Answer:

2/3 1/5 6/8

Step-by-step explanation:

3 0
3 years ago
What is the vertex of the parabola given by the equation y = x2 + 4? A. (2, 8) B. (-2, 8) C. (0, 4) D. (4, 0) E. (0, 0)
stira [4]

Vertex form is

y = a(x-p)^2 + q

We're practically in vertex form,

y = 1(x - 0)^2 + 4

That's a vertex at x=0, y=4, (0,4)

choice C

5 0
3 years ago
Read 2 more answers
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