All categories

3 years ago

Please just tell me if number one is right

Mathematics

2 answers:

sattari [20]3 years ago

8 0

Answer:

No the answer is square root {2}

Step-by-step explanation:

1/2+1/square root 2+ Square root 3/2 1\square root 2

Jlenok [28]3 years ago

6 0

Answer:

yup. looks right to me

Step-by-step explanation:

You might be interested in

A grocery store sells cans of mushrooms in three different sizes. This chart displays the prices. Which size is the best buy? Si

lorasvet [3.4K]

Answer:

22 oz for $3.49

Step-by-step explanation:

divide the price by the size so you can get the price per ounce
1.48/ 8 = 0.185

2.85/ 15 = 0.19

3.49/ 22 = 0.1586363636

7 0

3 years ago

If 3 cot theta= 2, find the value of 2sin theta -3cos theta /2sin theta +3cos theta

sergeinik [125]

Answer:

Step-by-step explanation:

Using the trigonometric identity

cotx = $\frac{cosx}{sinx}$

Given

3cotθ = 2 , then

3 $\frac{coso}{sino}$ = 2 ( multiply both sides by sinθ )

3cosθ = 2sinθ ( subtract 3cosθ from both sides )

2sinθ - 3cosθ = 0

Thus

$\frac{2sin0-3cos0}{2sin0+3cos0}$

= $\frac{0}{2sin0+3cos0}$

= 0

5 0

3 years ago

PLEASE HELP a three dight number has one more ten than it has hundreds, and it also has one more than twice as many units as ten

bija089 [108]

The reverse number of the three-digit number is 732

<h3>How to determine the reverse of the number?</h3>

Let the three-digit number be xyz.

So, the reverse is zyx

This means that

Number = 100x + 10y + z

Reverse = 100z + 10y + x

From the question, we have the following parameters:

y = x + 1

z = 1 + 2y

The sum is represented as:

100x + 10y + z + 100z + 10y + x = 10^3 - 31

100x + 10y + z + 100z + 10y + x = 969

Evaluate the like terms

101x + 101z + 20y = 969

Substitute y = x + 1

101x + 101z + 20(x + 1) = 969

101x + 101z + 20x + 20 = 969

Evaluate the like terms

101x + 101z + 20x = 949

121x + 101z = 949

Substitute y = x + 1 in z = 1 + 2y

z = 1 + 2(x + 1)

This gives

z = 2x + 3

So, we have:

121x + 101z = 949

121x + 101* (2x + 3) = 949

This gives

121x + 202x + 303 = 949

Evaluate the sum

323x = 646

Divide by 323

x = 2

Substitute x = 2 in z = 2x + 3 and y = x + 1

z = 2*2 + 3 = 7

y = 2 + 1 = 3

So, we have

x = 2

y = 3

z = 7

Recall that

Reverse = 100z + 10y + x

This gives

Reverse = 100*7 + 10*3 + 2

Evaluate

Reverse = 732

Hence, the reverse number of the three-digit number is 732

Read more about digits at:

brainly.com/question/731916

#SPJ1

8 0

1 year ago

What is the solution for this equation -9y=9

Valentin [98]

Divide both sides of this eq'n by -9. You'll get y = -1.

7 0

4 years ago

The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago