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3 years ago

If 3 cot theta= 2, find the value of 2sin theta -3cos theta /2sin theta +3cos theta

Mathematics

1 answer:

sergeinik [125]3 years ago

5 0

Answer:

Step-by-step explanation:

Using the trigonometric identity

cotx = $\frac{cosx}{sinx}$

Given

3cotθ = 2 , then

3 $\frac{coso}{sino}$ = 2 ( multiply both sides by sinθ )

3cosθ = 2sinθ ( subtract 3cosθ from both sides )

2sinθ - 3cosθ = 0

Thus

$\frac{2sin0-3cos0}{2sin0+3cos0}$

= $\frac{0}{2sin0+3cos0}$

= 0

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3 years ago

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