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Eva8 [605]
3 years ago
9

If 3 cot theta= 2, find the value of 2sin theta -3cos theta /2sin theta +3cos theta

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

0

Step-by-step explanation:

Using the trigonometric identity

cotx = \frac{cosx}{sinx}

Given

3cotθ = 2 , then

3\frac{coso}{sino} = 2 ( multiply both sides by sinθ )

3cosθ = 2sinθ ( subtract 3cosθ from both sides )

2sinθ - 3cosθ = 0

Thus

\frac{2sin0-3cos0}{2sin0+3cos0}

= \frac{0}{2sin0+3cos0}

= 0

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Part A:

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Part B:

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Part C:

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