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butalik [34]
3 years ago
9

Jasmine weigh 150ib he is loading a freight elevator with identical 72-pound boxes. The elevator can carry no more than 2000ib.

If Jasmine rides with the boxes,how many boxes can be loaded on the elevator?
Mathematics
1 answer:
const2013 [10]3 years ago
3 0

Answer:

Jasmine can load maximum of 25 boxes with herself on the elevator.

Step-by-step explanation:

Given:

Weight of Jasmine = 150 lb

Weight of each boxes  = 72 lb

Load elevator can carry = 2000 lb

we need to find the number of boxes that can be loaded

Let number of boxes be 'x'

Now we know that Maximum load the elevator can carry is 2000 lb.

So We can say Weight of jasmine plus Number of boxes multiplied by Weight of each boxes should be less than or equal to Load elevator can carry.

Framing in equation form we get;

150+72x\leq 2000

Solving the equation we get:

We will first Subtract 150 on both side;

150+72x-150\leq 2000-150\\\\72x\leq 1850

Now Dividing both side by 72 by using Division property we get;

\frac{72x}{72}\leq \frac{1850}{72}\\\\x\leq 25.69

Hence Jasmine can load maximum of 25 boxes with herself on the elevator.

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Hello from MrBillDoesMath!

Answer:

a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1


Discussion:

You may need to clean things up a bit but suppose that

S(1) = a-1

S(2) = a^2 -1

Since this is a geometric series, the geometric ratio is given by


S(2)/ S(1) =  (a^2 -1)/ (a-1)

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Conclusion:

S(2) = (a+1) S(1) = (a+1) (a-1)

S(3)  = (a+1) S(2) = (a+1) (a+1) (a-1)   = (a+1)^ (3-1) (a-1)

S(4) = (a+1) S(3)  = (a+1) * (a+1)^2 (a-1) ) = (a+1)^(4-1) (a-1)

in general.....

S(n) = (a+1)^ (n-1) (a-1)

So

S(6) = (a+1)^ (6-1) (a-1)

      =  (a-1) (a+1) ^ 5

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Hope I didn't screw something here!


Thank you,

MrB

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