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3 years ago

In the triangle shown, AC=BC and AB=4√2 how long are each of the legs

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

If we're to assume this is a right triangle, we can plug these numbers into the pythagorean theorem.

x^2 + x^2 = (4sqrt(2))^2

2x^2 = 32. Divide each side by 2.

x^2 = 16. Take the square root of each side.

x = 4, -4. But side lengths cannot be negative so,

x = 4.

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Answer:
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f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

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