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ella [17]
3 years ago
11

How do I write the linear equations. Please help ASAP THANK YOU

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

Well there is no linear equation that represents y as a function of x. You said it yourself, "The data CANNOT be modeled by a linear equation because the rate of change is not constant."

Step-by-step explanation:

There is none. y has random values.

You might be interested in
For the exponential equation <img src="https://tex.z-dn.net/?f=y%20%3D%203.4%280.66%29%5Ex" id="TexFormula1" title="y = 3.4(0.66
lisabon 2012 [21]

Answer:

Option: B is the correct answer.      

B)     Decay, y- intercept = 3.4, rate is 34%

Step-by-step explanation:

We are given an exponential equation as follows:

                    y=3.4(0.66)^x

We know that any exponential function of the type:

                                y=ab^x

is growth function if: b>1

and is a decay function if 0< b< 1

Hence, here we have: b=0.66<1

Hence, the function is a decay function.

Also, we know that the y-intercept of a function is the point where x=0

Hence, we take x=0

we have:  y=3.4\times (0.66)^0\\\\\\y=3.4

Hence, the y-intercept is:   3.4

Also, the rate of a function is denoted by 'r'

where b=1-r

    ⇒ 0.66=1-r

   ⇒   r=1-0.66

    ⇒ r=0.34

Hence, the rate is: 34%

          option: B is the correct answer.

4 0
3 years ago
Okay i have to do a whole test and i need help!! <br> The picture is up there!
Natalka [10]

Answer:

a is triangular prism :)

5 0
3 years ago
Read 2 more answers
Write an exponential function of the form f(x) = ab* whose graph passes through the
Andrews [41]

Answer:

Step-by-step explanation:

let f(x)=ab^x

when x=1,f(x)=6

6=ab

when x=2,f(x)=18

18=ab^2

divide

\frac{ab^2}{ab}=\frac{18}{6}\\b=3\\ab=6\\3a=6\\a=2\\f(x)=2(3)^x

4 0
4 years ago
Suppose that
Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

csc(B) = 13/12

sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12

The six  trigonometric functions of angle B are:

sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\

7 0
4 years ago
If Sue runs one mile every 7 minutes, and this relationship is graphed, which ordered pair would not be on the graph?
Free_Kalibri [48]
I don’t know this one
4 0
3 years ago
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