Explanation:
<em>Potas</em><em>sium</em><em> </em><em>has</em><em> </em><em>an</em><em> </em><em>atomi</em><em>c</em><em> </em><em>radii</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>greate</em><em>r</em><em> </em><em>t</em><em>han</em><em> </em><em>t</em><em>hat</em><em> </em><em>of</em><em> </em><em>lithiu</em><em>m</em><em> </em><em>th</em><em>at</em><em> is</em><em> </em><em>why</em><em> </em><em>pot</em><em>assium</em><em> </em><em>is</em><em> </em><em>more</em><em> </em><em>reactiv</em><em>e</em><em> </em><em>than</em><em> </em><em>lithi</em><em>um</em><em>.</em>
<em>tHx</em><em> </em><em>fOr</em><em> pOinTs</em><em>.</em><em>.</em><em>.</em>
In meiosis, DNA replication is followed by two rounds of cell division to produce four daughter cells, each with half the number of chromosomes as the original parent cell. The two meiotic divisions are known as meiosis I and meiosis II.
Explanation:
The answer to this would be d. Precipitation patterns .
Answer:
The heat required to melt 7.35 g of benzene at its normal melting point is 934.8 Joules.
The heat required to vaporize 7.35 g of benzene at its normal melting point is 2,893 Joules.
Explanation:
Mass of benzene = 7.35 g
Moles of benzene = 
Heat fusion of benzene,
1) Heat required to melt 7.35 g of benzene at its normal melting point = Q


(1 kJ = 1000 J)
2) Heat vaporization of benzene,
Heat required to vaporize 7.35 g of benzene at its normal melting point = Q


(1 kJ = 1000 J)
Answer: The density of the liquid is 
Explanation:
Density is defined as the mass contained per unit volume.
Given : Mass of the unknown liquid = 938 grams
Volume of the unknown liquid =
Putting in the values we get:
Thus the density of the liquid is
and the liquid is dimethyl sulfoxide.