Answer:
1. 0.45 mole
2. 49.95g
Explanation:
The following were obtained from the question:
Volume of solution = 300mL = 300/1000 = 0.3L
Molarity = 1.5 M
Mole of CaCl2 =?
1. We can obtain the mole of the solute as follow:
Molarity = mole of solute /Volume of solution
1.5 = mole of solute/0.3
Mole of solute = 1.5 x 0.3
Mole of solute = 0.45 mole
2. The grams in 0.45 mole of CaCl2 can be obtained as follow:
Molar Mass of CaCl2 = 40 + (35.5 x 2) = 40 + 71 = 111g/mol
Mole of CaCl2 = 0.45 mole
Mass of CaCl2 =?
Mass = number of mole x molar Mass
Mass of CaCl2 = 0.45 x 111
Mass of CaCl2 = 49.95g
The hardest to compress here would be the brick
To calculate the amount of the compound in the units of grams, we need to first obtain for the molar mass of the compound. We calculate as follows:
MgCl2 = <span>24.31 + (2 x 35.45) = 95.21 g/mol
</span><span>340 g MgCl2 ( 1 mol / 95.21 g ) = 3.57 mol MgCl2
Hope this answers the question. Have a nice day.</span>
Answer:
0.03 L
Explanation:
Step 1: Given data
- Initial volume of the balloon (V₁): 0.5 L
- Initial temperature of the balloon (T₁): 293 K
- Final volume of the balloon (V₂): ?
- Final temperature of the balloon (T₂): 20 K
Step 2: Calculate the final volume of the balloon
The balloon is filled with air. If we assume it behaves as an ideal gas, we can calculate the final volume of the balloon using Charles' law.
V₁/T₁ = V₂/T₂
V₂ = V₁ × T₂/T₁
V₂ = 0.5 L × 20 K/293 K = 0.03 L
