Please help for brainliest!!!!
1 answer:
Answer:
d)
Step-by-step explanation:
i¹= i
i²= -1
i³= -i
i⁴= 1
i¹²⁴= i^(124 +0)
i^124 . i^0
i^(4×31) . i^0 = 1³¹. i^0
1.i^0= i^0
= 1
a) i^179= i^(176+3)
i^176 . i³ = i^(4×44) . i³
1⁴⁴. i³ = 1. i³
= -i
b) i^582 = i^(580 + 2)
i^580 . i²= i^(4×145) . i²
1^145 . i²= 1.i²
= -1
c) i^165= i^(164+1)
i^164 . i¹ = i^(4×41) . i¹
1⁴¹ . i¹ = 1.i
= i
d) i^740= i^(740+0)
i^740 . i^0 = i^(4×185) . i^0
1^185 . i^0 = 1. i^0
= 1
i¹²⁴= i^740 = 1
You might be interested in
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H =
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer