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Eduardwww [97]
2 years ago
14

Sam has $2.25 in quarters and dimes, and the total number of coins is 12. How many quarters and how many dimes?

Mathematics
2 answers:
a_sh-v [17]2 years ago
8 0
N₁*$0.10 + n₂*$0.25 = $2.25

n₁ + n₂ = 12

-----------

This means that:

n₁ = 12 - n₂

And:

(12 - n₂)*$0.10 + n₂*$0.25 = $2.25

12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25

$1.20 + n₂*$0.05*(5-2) = $2.25

$1.20 + n₂*$0.05*3 = $2.25

$1.20 + n₂*$0.15 = $2.25

n₂*$0.15 = $2.25 - $1.20

n₂*$0.15 = $1.05

n₂ = ($1.05)/($0.15)

n₂ = 7

If n₂ = 7:

n₁ + 7 = 12

Therefore, n₁ = 5.

---------

Answer:

5 dimes and 7 quarters.
azamat2 years ago
7 0
The accurate answer would be 5 dimes and 7 quarters and if you add them up will equal 12 coins in total
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Answer:

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Parenthesis

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Answer- Follow the attachment attached herewith.

Solution-

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If we are moving in right ,we have to add in x co-ordinate and if we are moving left we have subtract from x co-ordinate. Likewise, if we are moving up, we have to add in y co-ordinate and if we are moving down, then we have to subtract from y co-ordinate.

As given in the question, we have move the triangle 4 units right and 5 units down,

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