Right triangle bc a^2+b^2=c^2. (Pythagorean theorem)
Answer:
y = (-3/4)x - 4
Step-by-step explanation:
The slopes of perpendicular lines are opposite reciprocals of each other. In other words, if the slope of one line is a/b, then the slope of the line perpendicular to it would be -b/a.
Here, the given slope is 4/3, so the slope of the perpendicular line is -3/4.
We are given a point (-4, -1) and we know the slope, so we can find the point-slope form of the line. Point-slope form is written as y - y1 = m(x - x1), where (x1,y1) is the point and m is the slope. Here, x1 = -4 and y1 = -1 and m = -3/4. So:
y - y1 = m(x - x1)
y - (-1) = (-3/4) * (x - (-4)) = (-3/4) * (x + 4)
y + 1 = (-3/4)x + (-3/4) * 4 = (-3/4)x - 3
y = (-3/4)x - 3 - 1
y = (-3/4)x - 4
Answer: D
Step-by-step explanation:
√8=2√2
and i cant see the first problem
Answer:
The x-intercepts of a function are when the graph/function crosses the x-axis when y = 0.
Step-by-step explanation:
