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Daniel [21]
3 years ago
11

C(4+3c) -0.75 (c+3) = plzz help

Mathematics
2 answers:
jonny [76]3 years ago
5 0
The answer is 3.25c+3c^2-2.25
Andreyy893 years ago
3 0

Answer:

if I am not mistaken the answer should be

11.25C?

Step-by-step explanation:

I did like terms to add 3c to 3c plus 4c minus .75 which would equal 11.25 c if it were to ask for expression then 12c-.75

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F plus 4 divided by h= 6
Sergeeva-Olga [200]
F is 8 h is 2 hope that helpssss
7 0
2 years ago
Could someone pkease help. i am not sure if i have the correct answer, thanks
Mama L [17]
I believe you are correct keep it up
5 0
3 years ago
Pls anwser this :) it’s math (5)
sleet_krkn [62]

Answer:

The answer is 4

Step-by-step explanation:

2/3 x 6= 4

4 0
3 years ago
The graph of a linear function intersects with the x axis at a point with an abscissa of 4 and with the y axis at a point with a
goldenfox [79]
We know that

points are
x intercept
A (4,0)

y intercept
B (0,11)

step 1
find the equation of a line
m=(y2-y1)/(x2-x1)--------> m=(11-0)/(0-4)------> m=-11/4

with m and the point B (0,11)
y-y1=m*(x-x1)y-11=(-11/4)*(x-0)---------> y=-(11/4)x+11

the answer is 
the formula of the function is y=-(11/4)x+11

see the attached figure

7 0
3 years ago
The weights of red delicious apples are approximately normally distributed with a mean of 9 Ounces and a standard deviation of 0
Simora [160]

Answer:

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

Step-by-step explanation:

Let X: weight of a red delicious apple, and B: the weight of the box and packing material.

The distribution that will represent W: the total weight of the packaged 5 randomly selected apples will be also normally distributed.

Applying the property of the mean: E(aX)=aE(X), the mean of W will be:

\mu_W=E(W)=E(5X+B)=5E(X)+E(B)=5*9+10=45+10=55

Applying the property of the variance: V(aX+b)=a^2V(X), the variance of W will be:

\sigma^2_W=V(W)=V(5X+B)=5^2V(X)+V(B)=25*0.75+0=18.75

The mean standard deviation of W will be the squared root of V(W):

\sigma_W=\sqrt{V(W)}=\sqrt{18.75}=4.33

The mean of W is 55 ounces.

The standard deviation of W is 4.33 ounces.

3 0
3 years ago
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