3 years ago

C(4+3c) -0.75 (c+3) = plzz help

Mathematics

2 answers:

jonny [76]3 years ago

5 0

The answer is 3.25c+3c^2-2.25

Andreyy893 years ago

3 0

Answer:

if I am not mistaken the answer should be

11.25C?

Step-by-step explanation:

I did like terms to add 3c to 3c plus 4c minus .75 which would equal 11.25 c if it were to ask for expression then 12c-.75

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Neporo4naja [7]

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3 years ago

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")