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Reptile [31]
3 years ago
15

Which statement is an example of heat transfer by convection?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer: Hot air from the sand rose and was replaced by cool air blowing in from the ocean as a sea breeze.

Step-by-step explanation:

sorry it's late but hopefully it will help others

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A pair of fair dice is rolled.
mezya [45]
A) 4/36, or 1/9
b) 1-1/9=8/9
5 0
3 years ago
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Help clear the fractions I need more help
marishachu [46]

Answer:

x = \frac{43}{6}

Step-by-step explanation:

Given

\frac{3}{4} x - 5 = \frac{3}{8}

Multiply through by 8 ( the LCM of 4 and 8 ) to clear the fractions

6x - 40 = 3 ( add 40 to both sides )

6x = 43 ( divide both sides by 6 )

x = \frac{43}{6}

3 0
3 years ago
For what value of k will k+9,2k-1 and 2k+7 are the consecutive terms of an A.P
Stolb23 [73]

k = 18

the common difference d of an arithmetic sequence is

d = a₂ - a₁ = a₃ - a₂ = ....

a₂ - a₁ = 2k - 1 - k - 9 = k - 10 and

a₃ - a₂ = 2k + 7 - (2k - 1) = 2k + 7 - 2k + 1 = 8, hence

k - 10 = 8 ⇒ k = 8 + 10 = 18

the 3 consecutive terms are

27, 35, 43


8 0
3 years ago
Only 23 out of 50 people in the class passed the exam. What percent of the class passed the exam?
Black_prince [1.1K]

Answer:

46%

Step-by-step explanation:

For percents, we want to make the number out of 100.  23/50 is the same as 46/100.  From fraction knowledge, 46/100 is 46%.

5 0
3 years ago
Read 2 more answers
Suppose that administrators of a large school district wish to estimate the proportion of children in the district enrolling in
11Alexandr11 [23.1K]

Answer:

95% z-confidence interval for the proportion of all children enrolled in kindergarten who attended preschool is between a lower limit of 0.528 and an upper limit of 0.772.

Step-by-step explanation:

Confidence interval = p + or - zsqrt[p(1-p) ÷ n]

p is sample proportion = 39/60 = 0.65

n is the number of children sampled = 60

Confidence level (C) = 95% = 0.95

Significance level = 1 - C = 1 - 0.95 = 0.05

Divide significance level by 2 to obtain critical value (z)

0.05/2 = 0.025 = 2.5%

z at 2.5% significance level = 1.96

zsqrt[p(1-p) ÷ n] = 1.96sqrt[0.65(1-0.65) ÷ 60] = 1.96sqrt[0.2275 ÷ 60] = 1.96sqrt(3.792×10^-3) = 1.96×0.062 = 0.122

Lower limit = p - 0.122 = 0.65 - 0.122 = 0.528

Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

5 0
3 years ago
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