Answer:
D. The mean debt of all students and the proportion holding student loans are both parameters, but the values 30% and $18,450 are statistics.
Step-by-step explanation:
Parameters and statistic are numerical characteristic derived form out data. The distinction between both are : paatwrs are numeric characteristic which are calculated from the population data while those obtained form the sample. Data are called statistic.
The 30% and mean of 18450 are derived from the sample data.
However, the proportion of all students holding a student loan and the mean value is $18450.
As all students represents the total population.
1)16^2 or 4^4
2)3^2
3)4^2
4)5^2
5)15^2
6)14^2
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Answer:
48
Step-by-step explanation:
8 +(200/5)=48
hope this helped
Complement of an angle = 90° - x.
Supplement of the complement of an angle = 180 - (90 - x).
= 180 - 90 + x
= 90 + x
Supplement of the complement of an angle less the complement of an angle = (90 + x) - (90 - x)
= 90 + x - 90 + x
= 2x
Now, the quotient of the supplement of the angle and the number 3 is .
It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.
Therefore, 2x =
Multiply both sides by 3.
6x = 180 - x + 219
= 399 - x
Add x to both sides.
6x + x = 399
7x = 399
Divide both sides by 7.
x = 57
Hence, the required angle = 57°.