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bagirrra123 [75]
3 years ago
5

Mr. Miller built a rectangular frame for a sandbox in his back yard. He used boards that measured 414

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

Answer:

the answer is 20

Step-by-step explanation:

umka21 [38]3 years ago
4 0

Answer:

jio;ji

Step-by-step explanation:

jhjlk

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If the volume of a cylinder is 90 inches and what is the volume of a cone?
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  • The ans is D)1/3 in my point of view...
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Micheal is taking a survey of students at his high school to find out how many hours they work per week. He surveys all of the s
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Teesha is in a french club. there are 10 freshman, 12 sophomores, 15 juniors, and 30 seniors in the club. the advisor is going t
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3 years ago
Hi, I have no clue how to do proportions and can you explain how to do this? If you can't that's alright.
bekas [8.4K]

___________________

Please, give me some minutes to take over your question

______________________________________

Rate = miles / time

8/t = 7/ 35

Dividing by 7

8/t = 7/ 35

8/ 7t = 1/ 35

Multiplying by t

8/7 = t/35

_____________

Options

1) 8/t = 35/ 7 (False, t/8 = 35/ 7 )

2) t/8 = 7/ 35 (False, t/8 = 35/ 7 )

3) 8/7 = t/ 35 (TRUE)

4) 7/8 = t/35 (False, 8/7 = t/ 35 )

__________________

Answer

3) 8/7 = t/ 35 (TRUE)

4 0
1 year ago
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
3 years ago
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