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Radda [10]
3 years ago
11

What is the probability that it is not blue?

Mathematics
1 answer:
Alisiya [41]3 years ago
8 0
1/3 chances the bubblegum is blue. To solve this problem you add all of the bubblegum together so 25+20+15 to get 60 then express it as a fraction to show only the blue pieces which would be 20/60 and you can simplify it to 1/3 or 33.33%
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Suppose that you are a city planner who obtains and sample of 20 randomly selected members of a mid-sized town in order to deter
Dmitry_Shevchenko [17]

Answer:

The critical value for the 95% confidence interval is z = 1.96.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96.

The critical value for the 95% confidence interval is z = 1.96.

5 0
3 years ago
What addition expressions have a value of 8
ololo11 [35]

Step-by-step explanation:

1 + 7 = 8

2 + 6 = 8

3 + 5 = 8

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\sqrt{4} + \sqrt{4} + \sqrt{4} + \sqrt{4} = 8

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5 0
3 years ago
Read 2 more answers
Evaluate m^0 - n^2 for m = 2 and n = -1.<br><br> A. -1<br> B. 0<br> C. 1
galben [10]

Answer:

B) 0

Step-by-step explanation:

4 0
3 years ago
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A veterinarian studying causes of enteroliths in horses suspects feeding too much alfalfa may be a culprit. The veterinarian hyp
Hatshy [7]

Answer: 0.022

Step-by-step explanation:

Let p be the population proportion of horses were fed mostly alfalfa.

We are given that :

H_0: p=0.67\\ H_a:p>0.67 , since alternative hypothesis (H_a) is right tailed , so the test is a right-tailed test.

Also, we have

Sample size= 62

Sample proportion= \hat{p}=\dfrac{49}{62}\approx0.79

Test statistic for population proportion:-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Substitute all values ,

z=\dfrac{0.79-0.67}{\sqrt{\dfrac{0.67(1-0.67)}{62}}}\\\\=\dfrac{0.12}{\sqrt{0.00356612903226}}\\\\=\dfrac{0.12}{0.059717}\\\\=2.00947551836\approx2.01

P-value for right tailed test :

P(z>2.01)=1-P(z<2.01)              [∵P(Z>z=1-P(Z<z))]

=1-0.9777844                     [By using z-value table]

=0.0222156≈0.022

Hence, the P-value for this test is <u>0.022</u> .

5 0
3 years ago
In what situation can you use only multiplication to find equivalent fractions? Give an example
algol [13]
1/2•1/2=1/4 since The numerators are both ones 1×1 equals one but the denominators are both two so 2×2 = 4 that’s how you get 1/4
6 0
3 years ago
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