200/160 as a percentage (200 over 160)
2 answers:
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Answer:
A. 1 rectangle, 2 triangles
B. AB = AE = 5
C. 36.5 square units
Step-by-step explanation:
<h3>A.</h3>The attached figure shows 1 rectangle (square) and two triangles.
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<h3>B.</h3>These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:
AB = 2 -(-3) = 5
AE = 3 -(-2) = 5
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<h3>C.</h3>The area of the square is ...
A = s^2 = 5^2 = 25
The area of triangle BCF is ...
A = 1/2bh = 1/2(3)(5) = 15/2
The area of triangle CDE is ...
A = 1/2bh = 1/2(8)(1) = 4
The total area is the sum of the areas of the square and two triangles:
total area = 25 +7.5 +4 = 36.5 . . . square units
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<em>Additional comment</em>
We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...
A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5
Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...
32.5 +4 = 36. 5 . . . . square units
Answer:
Step-by-step explanation:
Given equation of line:
To find the equation of line perpendicular to the line of the given equation and passes through point (8,2).
Applying slope relationship between perpendicular lines.
where and
are slopes of perpendicular lines.
For the given equation in the form the slope
can be found by comparing
with standard form.
∴
Thus slope of line perpendicular to this line would be given as:
∴
The line passes through point (8,2)
Using point slope form:
Where and
So,
Using distribution.
Adding 2 to both sides.
Thus the equation of line in standard form is given by: