Answer:
D
Step-by-step explanation:
divide 10 times starting with 100.
The answer is 25/256 or 0.09765625
H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Answer:
{2, 6, 14}
Step-by-step explanation:
Using f(x) = 4x + 6 with a domain of {-1, 0, 2 }, find the range.
To get the range, we will substitute the values of the domain into the given function as shown;
when x = -1
f(-1) = 4(-1)+6
f(-1) = -4+6
f(-1) = 2
when x = 0
f(0) = 4(0)+6
f(0) = 0+6
f(0) = 6
when x = 2
f(2) = 4(2)+6
f(2) = 8+6
f(2) = 14
Hence the required range are {2, 6, 14}
X = 9
you multiply both sides by 3 because you have to get rid of it and what you do to one side you do to the other then you divide both sides by 2 to isolate the variable. i hope that makes sense.
