I'm assuming the equation is x^3 = 216 or
(both mean the same thing)
If so, then the solution to x^3 = 216 is
x = 6
<span>We can find this by taking the cube root of both sides
</span>x^3 = 216
x = 216^(1/3) .... 1/3 power means cube root
x = 6
Checking the answer:
x^3 = 216
6^3 = 216
6*6*6 = 216
216 = 216
Answer is confirmed
So once again
the answer is x = 6. This is assuming the initial assumption made at the top of the problem holds up.
Accordinly to the details, i think that A could work.
Answer:
Ok, so this is a word game, basically. The answer would be no, he is not correct BECAUSE...⬇
Step-by-step explanation:
It looks to be asking "Is Jesse correct in saying that he has EXACTLY one liter left?" That would be a no because even though 10L-7L= 3L, the problem asks if he does have exactly ONE liter left, and Jesse says he DOES. But, according to my little equation above, if he drank 7L, he would have 3L left, NOT 1L. Soo, my answer would be "No, Jesse is not correct because 10L-7L=3L and if he says there is 1L left, he would not be correct because there are 3L left." Hope that helps!
Answer:
i don't really know soryyyy
Step-by-step explanation:
Answer:
( $74.623, $83.777)
The 90% confidence interval is = ( $74.623, $83.777)
Critical value at 90% confidence = 1.645
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $79.20
Standard deviation r = $10.41
Number of samples n = 14
Confidence interval = 90%
Using the z table;
The critical value that should be used in constructing the confidence interval.
z(α=0.05) = 1.645
Critical value at 90% confidence z = 1.645
Substituting the values we have;
$79.20+/-1.645($10.42/√14)
$79.20+/-1.645($2.782189528308)
$79.20+/-$4.576701774067
$79.20+/-$4.577
( $74.623, $83.777)
The 90% confidence interval is = ( $74.623, $83.777)
