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vodka [1.7K]
3 years ago
13

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. The length of the h

ypotenuse is 22 inches more than twice the length of the shorter leg. Find the side lengths of the triangle.
Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

Step-by-step explanation:

Let x represent the length of the hypotenuse.

Let y represent the length of the the shorter leg.

Let z represent the length of the longer leg.

The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. It means that

z = 2y + 20

The length of the hypotenuse is 22 inches more than twice the length of the shorter leg. It means that

x = 2y + 22

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Therefore,

(2y + 22)² = y² + (2y + 20)²

(2y + 22)(2y + 22) = y² + (2y + 20)(2y + 20)

= 4y² + 44y + 44y + 484 = y² + 4y² + 40y + 40y + 400

4y² + 88y + 484 = y² + 4y² + 80y + 400

4y² + 88y + 484 = 5y² + 80y + 400

5y² - 4y²+ 80y - 88y + 400 - 484

y² - 8y - 84 = 0

y² + 6y - 14y - 84 = 0

y(y + 6) - 14(y + 6)

y - 14 = 0 or y + 6 = 0

y = 14 or y = - 6

The shorter length cannot be negative hence y = 14 inches

The length of the shorter side is 14 inches.

The length of the hypotenuse is

(2 × 14) + 22 = 50 inches

The length of the longer side is

(2 × 14) + 20 = 48 inches

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